[AusNOG] Looking for employees? Melbourne based

[Alex Samad - Yieldbroker]

Hmm
So
2^96 + 1 bytes have to pass through the port to roll over
10 ^ 9 bits or 2 ^ 9 / 8 but that's one way .... If the counter it total bytes not rx or tx then * 2


2^96 = 79228162514264337593543950336
10 ^ 9 / 8 = 125000000


( 2^96 ) / ( 10 ^ 9 / 8 )
633825300114114700748
( ( 2^96 ) / ( 10 ^ 9 / 8 ) ) / 60 / 60 / 24
7335940973542994 days
( ( 2^96 ) / ( 10 ^ 9 / 8 ) ) / 60 / 60 / 24 / 7
1,047,991,567,648,999 weeks

( ( 2^96 ) / ( 10 ^ 9 / 8 ) ) / 60 / 60 / 24 / 7 / 52
20,153,683,993,249 years

A

From: AusNOG [mailto:ausnog-bounces at lists.ausnog.net] On Behalf Of Paul Brooks
Sent: Friday, 11 October 2013 8:49 PM
To: Joshua D'Alton; Damian Guppy
Cc: ausnog at lists.ausnog.net
Subject: Re: [AusNOG] Looking for employees? Melbourne based

Hmmm - I had roughly 25.5 days. Maybe I shouldn't hire myself :-(

(Need more beer before delving into Wolfram Alpha again)

P.

On 11/10/2013 8:37 PM, Joshua D'Alton wrote:
20 098 468 420 665 737.6 years

On Fri, Oct 11, 2013 at 8:33 PM, Damian Guppy <the.damo at gmail.com<mailto:the.damo at gmail.com>> wrote:

On Fri, Oct 11, 2013 at 3:48 PM, Paul Brooks <pbrooks-ausnog at layer10.com.au<mailto:pbrooks-ausnog at layer10.com.au>> wrote:
How long will a gigabit ethernet router port at full utilisation cause the
byte-counter to wrap, if the byte-counter is a 96-bit register)

I got 18 700 000 000 000 years, if im wrong i blame google calculator :P

--Damian

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